Electromagnetic Waves
Maxwell's displacement current, accelerating charges, transverse E & B wave speed, energy & momentum, and complete EM spectrum uses.
Topic 8.2: Ampere-Maxwell Consistency & Displacement Current
B. Now bulge that same rim into a deep tiffin-box dipping BETWEEN the empty plates where zero electrons cross — suddenly Ampere's old law predicts B = 0 at the exact same rim! James Clerk Maxwell solved this puzzle: a changing electric field in the gap acts just like current!id = ε₀ dΦEdt (created by changing electric flux, zero electron flow!)∮ B · dl = μ₀ (ic + id) = μ₀ [ ic + ε₀ dΦEdt ]ic = I, id = 0 • Air gap: ic = 0, id = I • Total ic + id is continuous everywhere!id = ε₀ dΦE/dt!E = Q / (ε₀A) grows stronger every millisecond. That growing electric field creates circular magnetic field loops outside the plates identical to real wire current!- 1The Tiffin-Box Inconsistency: Two surfaces sharing the same circular loop — a flat disc cutting the wire (
ienc = I) and a pot/tiffin-box passing inside the capacitor gap (ienc = 0) — gave contradicting values for∮ B · dlin old Ampere's Law! - 2Proving
id = icin a Capacitor: Electric flux between plates isΦE = E A = (Q / ε₀ A) A = Q / ε₀.
Differentiating:id = ε₀ dΦEdt = ε₀ (1ε₀ dQdt) = dQdt = ic! - 3Capacitor Voltage Shortcut: Since
Q = C V, displacement current inside a capacitor is simplyid = C (dVdt)!
4 μF parallel-plate capacitor is charged so the potential difference across its plates rises at 5 × 10⁵ V/s. What is the displacement current between the plates? id = C (dV/dt) = (4 × 10⁻⁶) × (5 × 10⁵) = 2.0 A (exact match to wire conduction current!).
id = ic numerically, yet ZERO conduction electrons cross the gap! (2) Once the capacitor is fully charged by steady DC (V constant), dΦE/dt = 0 ⇒ BOTH ic = 0 and id = 0! (3) Even though called "displacement current", its SI unit is still Ampere (A)!Topic 8.3.1: Accelerating Charges as Sources of EM Waves
E and B break loose and fly away as EM waves!v=0): E only • Constant velocity (a=0): E + B • Accelerating (a≠0): Radiates EM Waves!ν emits EM wave of the EXACT same frequency ν!E creates changing B → creates changing E → needs NO medium!- 1Why Acceleration Is Essential: Maxwell predicted that a harmonically oscillating electric dipole (electrons surging up & down a metal rod at frequency
ν) generates time-varyingEandBfields that regenerate each other and detach into space! - 2Frequency Lock: If an electron oscillates at
νcycles per second, the emitted EM wave MUST carry frequencyνand wavelengthλ = c / ν(only speedcand wavelength change inside glass/water, NEVER frequency!). - 3Hertz Experiment (1887) & J.C. Bose: Heinrich Hertz produced ~5 m radio waves with a spark gap and caught tiny sparks on a distant detector loop; Jagadish Chandra Bose generated millimetre-scale microwaves in Kolkata!
ν = 10⁹ Hz (1 GHz). What is the frequency and wavelength of the emitted EM wave in vacuum?• Frequency =
10⁹ Hz (exact match!) • Wavelength λ = c / ν = (3 × 10⁸) / 10⁹ = 0.3 m (Microwave!).
v = constant) radiate electromagnetic waves? NO! It creates both E and B fields carried along with it, but radiates ZERO EM waves! Only accelerated charges (including charges circling at constant speed, because centripetal acceleration a ≠ 0!) emit EM radiation!Topic 8.3.2: Transverse Nature of E, B & Propagation c = 1/√(μ₀ε₀)
E) while the other waves side-to-side (B) in perfect lockstep, and the ripple shoots forward along the third perpendicular axis (E × B)! When Maxwell combined electric ε₀ and magnetic μ₀ constants, out popped 3 × 10⁸ m/s — proving light itself is an EM wave!E ⊥ B ⊥ v • Travels along E × B • IN PHASE (peak together!)c = 1√(μ₀ε₀) = 3 × 10⁸ m/s • E₀B₀ = c • Medium: v = 1√(με) = cn!Ex = E₀ sin(kz − ωt), By = B₀ sin(kz − ωt) with k = 2πλ, ω = 2πν, c = ωk!E and B are 90° apart in SPACE (axes), yet 0° apart in TIME (strictly in phase)! Check propagation axis with E × B!î × ĵ = k̂! If electric vector E wiggles up along +y (ĵ) and magnetic vector B wiggles sideways along +z (k̂), then ĵ × k̂ = +î — so the wave blasts forward along +x!- 1Vacuum Speed from Constants: Plugging
μ₀ = 4π × 10⁻⁷ T·m/Aandε₀ = 8.854 × 10⁻¹² C²/(N·m²)into Maxwell's wave speed givesc = 1√(μ₀ε₀) = 3.0 × 10⁸ m/s— matching the measured speed of light! Inside a medium,v = c / √(μr εr). - 2Same Speed for ALL Wavelengths in Vacuum: Gamma rays, X-rays, visible light, and radio waves ALL travel at the exact same speed
c = 3 × 10⁸ m/sin vacuum! - 3Reading Wave Equations: Given
By = 2×10⁻⁷ sin(0.5×10³ x + 1.5×10¹¹ t): notice the+sign means wave moves along−x! Alsok = 500 m⁻¹ ⇒ λ = 2π/500 = 1.26 cm,ω = 1.5×10¹¹ ⇒ ν = ω/(2π) = 23.9 GHz, andE₀ = c B₀ = 60 V/m!
+x. At an instant, E = 6.3 ĵ V/m. Find B.• Magnitude:
B = E / c = 6.3 / (3 × 10⁸) = 2.1 × 10⁻⁸ T.• Direction: Need
E × B along +î. Since (+ĵ) × (+k̂) = +î, B = 2.1 × 10⁻⁸ k̂ T!
E and B are 90° out of phase in time! FALSE: E and B peak together and hit zero together — phase difference is 0° (they are perpendicular only in spatial direction!). (2) Direction is ALWAYS E × B (NOT B × E!). (3) Watch (kx + ωt) vs (kx − ωt): − travels along +x, + travels along −x!Topic 8.3.2: Energy Density, Momentum & Wave Intensity
uE = ½ ε₀ Erms² EQUALS avg magnetic uB = Brms²2μ₀!uavg = ½ ε₀ E₀² = ε₀ Erms² = B₀²2μ₀ = Brms²μ₀ (J/m³)I = uavg · c = ½ ε₀ c E₀² (W/m²) • Momentum: p = Uc (absorb) or 2Uc (reflect)!2U/c) compared to a black absorber (U/c)!E₀ = c B₀ makes electric numbers look 3 × 10⁸ times bigger than magnetic Tesla numbers, plug them into energy formulas and both carry the EXACT same 50% share of wave energy!- 1Proving Equal Energy Share: Instantaneous electric energy density is
uE = ½ ε₀ E²and magnetic isuB = B²/(2μ₀). UsingB = E/candc² = 1/(μ₀ε₀):uB = E²2μ₀ c² = ½ ε₀ E² = uE! Total average densityuavg = 2 uE,avg = ½ ε₀ E₀² = ε₀ Erms²! - 2Wave Intensity (
I): Energy crossing unit perpendicular area per second:I = EnergyArea · Time = uavg · c = ε₀ c Erms²(W/m²). - 3Momentum & Radiation Pressure: Total energy
Uabsorbed completely transfers momentump = U / c(pressurePrad = I / c). On a 100% reflecting mirror, momentum change doubles top = 2U / c(Prad = 2I / c)!
I = 90 W/m² hits a 2.0 m² black solar absorber for 10 s:• Energy delivered:
U = I · A · t = 90 × 2.0 × 10 = 1800 J.• Momentum transferred:
p = U / c = 1800 / (3 × 10⁸) = 6.0 × 10⁻⁶ kg·m/s (if mirror → 1.2 × 10⁻⁵ kg·m/s!).
E₀ vs RMS Erms: total average energy density is ½ ε₀ E₀² (with ½!) OR ε₀ Erms² (NO ½, because Erms² = E₀²/2 doubled for E + B!). (2) Always check whether the surface absorbs (U/c) or perfectly reflects (2U/c)!Topic 8.4.1 – 8.4.4: Radio, Microwaves, Infrared & Visible Spectrum Uses
| Band | Wavelength λ | Source / Production | Detector & Key Uses |
|---|---|---|---|
| Radio Waves | > 0.1 m | Oscillating electrons in LC/aerials | Receiver aerials; AM/FM radio, TV, UHF mobile phones |
| Microwaves | 0.1 m – 1 mm | Klystron, Magnetron, Gunn diode | Point-contact diodes; Radar, satellites, microwave ovens |
| Infrared (IR) | 1 mm – 700 nm | Hot bodies, vibrating atoms/molecules | Thermopiles, bolometer; Remotes, physiotherapy, greenhouse warmth |
| Visible Light | 700 – 400 nm | Valence atomic electron transitions | Human eye, photocells, camera film; Vision & photosynthesis |
ν = 100 MHz (10⁸ Hz). Find its wavelength:λ = c / ν = (3 × 10⁸) / (100 × 10⁶) = 3.0 m (Right inside the Radio band!).
Topic 8.4.5 – 8.4.7: Ultraviolet, X-Rays & Gamma Rays Applications & Safety
E = hν) that they become double-edged tools: Ultraviolet (UV) kills bacteria in water purifiers, X-rays peer through skin to photograph broken bones, and nuclear Gamma rays blast cancer tumours — yet over-exposure can harm living cells unless properly shielded!| Band | Wavelength λ | Production | Uses & Safety |
|---|---|---|---|
| Ultraviolet (UV) | 400 nm – 1 nm | Inner-shell atomic transitions, sun, UV lamps | Water purifiers (kills germs), LASIK eye surgery; Ozone blocks solar UV-B/C; glass absorbs UV |
| X-Rays | 1 nm – 10⁻³ nm | Fast electrons bombarding heavy metal target | Medical fracture imaging, crystal structure, security scans; avoid over-exposure (cell/DNA damage) |
| Gamma Rays | < 10⁻³ nm | Nuclear reactions & radioactive nuclear decay | Destroy cancer cells (radiotherapy), sterilisation; needs thick lead/concrete shielding |
10⁻¹⁰ m), red light (6800 Å), and radio waves (500 m)?Answer: SPEED IN VACUUM (
c = 3 × 10⁸ m/s)! Only frequency ν and wavelength λ differ!
Solved Previous Year Questions (Kerala DHSE & NCERT)
Q1 (Kerala HSE March • 2 Marks): Define displacement current. Write the modified Ampere-Maxwell circuital law.
id = ε₀ (dΦE/dt).Ampere-Maxwell Law:
∮ B · dl = μ₀ [ ic + ε₀ (dΦE/dt) ].Q2 (Kerala HSE Say • 2 Marks): A parallel-plate capacitor of capacitance 2 μF is being charged so that the voltage across plates changes at 10⁵ V/s. Find the displacement current between the plates.
ΦE = Q/ε₀ = C V / ε₀ ⇒ id = ε₀ (dΦE/dt) = C (dV/dt).id = (2 × 10⁻⁶ F) × (10⁵ V/s) = 0.2 A.Q3 (Kerala HSE March • 2 Marks): State any four properties of electromagnetic waves.
2. Purely transverse:
E ⊥ B ⊥ propagation (E × B), oscillating in phase.3. Travel in vacuum at
c = 1/√(μ₀ε₀) = 3 × 10⁸ m/s (no medium required).4. Carry energy (50% electric, 50% magnetic) and momentum
p = U/c.Q4 (NCERT / HSE Model • 3 Marks): The magnetic field in a plane EM wave is B_y = 2 × 10⁻⁷ sin(0.5 × 10³ x + 1.5 × 10¹¹ t) T. Find (a) wavelength & frequency, (b) direction of propagation, and (c) electric field equation.
k = 0.5×10³ m⁻¹ ⇒ λ = 2π/k ≈ 1.26 cm; ω = 1.5×10¹¹ rad/s ⇒ ν = ω/(2π) ≈ 23.9 GHz.(b) Plus sign in
(kx + ωt) ⇒ wave moves along −x.(c)
E₀ = c B₀ = 3×10⁸ × 2×10⁻⁷ = 60 V/m. Since E × B must point −î and B is along +ĵ, E is along +k̂: E_z = 60 sin(0.5×10³ x + 1.5×10¹¹ t) V/m.Q5 (Kerala HSE March • 2 Marks): Name the EM waves used in (i) aircraft radar & microwave ovens, and (ii) TV remote controls & greenhouse warmth. State how microwaves heat food.
• (ii) Infrared (IR) waves.
Q6 (Kerala HSE Say • 2 Marks): Which electromagnetic radiation are welders protected against by special glass goggles? Why is the stratospheric ozone layer vital for life on Earth?
Similarly, Earth's stratospheric ozone (O₃) layer absorbs damaging solar UV radiation before it reaches living organisms.
Q7 (Kerala HSE Model • 2 Marks): Give one source and one medical application each for X-rays and Gamma rays.
• Gamma rays: Emitted during radioactive decay of atomic nuclei; used in radiotherapy to destroy cancer tumours.
Q8 (NCERT / DHSE Numerical • 2 Marks): Light with energy flux 18 W/cm² falls at normal incidence on a non-reflecting surface of area 20 cm² for 30 minutes. Find total momentum delivered.
U = I · A · t = 18 × 20 × (30 × 60) = 6.48 × 10⁵ J.For complete absorption:
p = U / c = (6.48 × 10⁵) / (3 × 10⁸) = 2.16 × 10⁻³ kg·m/s.