NCERT Plus Two (Class 12) Chemistry • Chapter 6

Haloalkanes and Haloarenes

Classification, Preparation, SN1 vs SN2 Mechanisms, Optical Activity & Chirality, Saytzeff Elimination, Haloarene Reactivity & Polyhalogens

📄 Official NCERT Textbook PDF

Topic 6.1 – 6.3: Classification (Allylic, Benzylic, Vinylic, Aryl), IUPAC Naming & Nature of the C–X Bond

Did you know life-saving medicines and even hormones inside your own body carry halogen atoms? Soil bacteria produce the chlorine-rich antibiotic chloramphenicol to fight typhoid fever, your thyroid gland makes the iodine hormone thyroxine (whose deficiency causes goitre), doctors prescribe chloroquine against malaria and halothane as a surgical anaesthetic, and chemists even test fully fluorinated compounds as synthetic blood substitutes! Yet one tiny structural detail—whether the halogen sits on an sp3 carbon (haloalkane) or directly on a flat sp2 carbon (haloarene / vinyl halide)—changes the molecule's entire chemical personality.

Replacing one or more hydrogen atoms of an aliphatic or aromatic hydrocarbon with halogen atoms (F, Cl, Br, I) yields haloalkanes (alkyl halides) and haloarenes (aryl halides), respectively.

1. Classification of Organohalogen Compounds (6.1)

  • By Number of Halogens: Mono- (C2H5X), Di- (XCH2CH2X), or Polyhalogen (tri-, tetra-, etc.) compounds.
  • Dihalides (Same Halogen):
    • Geminal dihalides (gem-dihalides): Both halogens on the same carbon. Common name: alkylidene halides (e.g., CH3CHCl2 = Ethylidene chloride / 1,1-Dichloroethane).
    • Vicinal dihalides (vic-dihalides): Halogens on adjacent carbons. Common name: alkylene dihalides (e.g., ClCH2–CH2Cl = Ethylene dichloride / 1,2-Dichloroethane).
  • Compounds with sp3 C–X Bond:
    • Alkyl halides (R–X, CnH2n+1X): Classified as Primary (1°), Secondary (2°), or Tertiary (3°) based on the carbon holding X.
    • Allylic halides: X is bonded to an sp3 carbon adjacent to a C=C double bond (e.g., CH2=CH–CH2Br, 3-Bromopropene).
    • Benzylic halides: X is bonded to an sp3 carbon attached directly to an aromatic ring (e.g., C6H5CH2Cl = Benzyl chloride).
  • Compounds with sp2 C–X Bond:
    • Vinylic halides: X is bonded directly to an sp2 carbon of a C=C double bond (e.g., CH2=CHCl, Chloroethene).
    • Aryl halides: X is bonded directly to an sp2 carbon of an aromatic ring (e.g., Bromobenzene, p-Chlorotoluene).

2. Common & IUPAC Nomenclature Highlights (6.2, Table 6.1)

StructureCommon NameIUPAC NameClass
CH3CH2CH(Cl)CH3sec-Butyl chloride2-Chlorobutane2° Alkyl halide
(CH3)3CCH2Brneo-Pentyl bromide1-Bromo-2,2-dimethylpropane1° Alkyl halide
(CH3)3CBrtert-Butyl bromide2-Bromo-2-methylpropane3° Alkyl halide
CH2=CHClVinyl chlorideChloroetheneVinylic (sp2)
CH2=CH–CH2BrAllyl bromide3-BromopropeneAllylic (sp3)
C6H5CH2ClBenzyl chlorideChlorophenylmethaneBenzylic (sp3)
NCERT Examples 6.1 & 6.2:
• C5H11Br has 8 structural isomers: Four 1° (1-bromopentane, 1-bromo-3-methylbutane, 1-bromo-2-methylbutane, 1-bromo-2,2-dimethylpropane), three 2° (2-bromopentane, 3-bromopentane, 2-bromo-3-methylbutane), and one 3° (2-bromo-2-methylbutane).
• Alkenyl numbering rule: Give C=C double bond the lower locant over halogen! E.g., CH3CH=CHCH(Br)CH3 → 4-Bromopent-2-ene; CH2=C(CH3)CH2Br → 3-Bromo-2-methylpropene.

3. Nature of the C–X Bond (6.3, Table 6.2)

Because halogens are more electronegative than carbon, the C–X bond is polarised: Cδ+–Xδ−. Going down Group 17 (F → Cl → Br → I), atomic size increases, so C–X bond length increases while bond enthalpy decreases:

BondBond Length (pm)Bond Enthalpy (kJ mol-1)Dipole Moment (Debye)
CH3–F1394521.847
CH3–Cl1783511.860 (Highest!)
CH3–Br1932931.830
CH3–I2142341.636
Two classic Kerala Board traps: (1) CH3Cl has a slightly HIGHER dipole moment (1.860 D) than CH3F (1.847 D) even though F is more electronegative—because dipole moment μ = q × d, and the much longer C–Cl bond length (178 pm vs 139 pm) outweighs fluorine's higher electronegativity! (2) Always check whether X is attached directly to C=C (vinylic, sp2) or one carbon away from C=C (allylic, sp3)!

Topic 6.4 – 6.5: Preparation of Haloalkanes & Haloarenes (SOCl₂, Markovnikov, Finkelstein, Swarts & Sandmeyer)

Suppose you run a pharmaceutical plant and need ultra-pure ethyl chloride from ethanol without spending hours purifying liquid mixtures. Add thionyl chloride (SOCl2)! Its two side-products—SO2 and HCl—are gases that bubble straight out of the flask, leaving behind pure haloalkane! And what if you need an alkyl iodide or fluoride that resists direct synthesis? Chemists use a clever salt-swap trick: precipitate insoluble NaCl in dry acetone (Finkelstein) or swap with silver fluoride (Swarts)!

1. From Alcohols (Best Lab Route for Alkyl Halides, 6.4.1)

  • R–OH + SOCl2 → R–Cl + SO2(g)↑ + HCl(g)↑ — Preferred method because both byproducts are escapable gases, yielding pure alkyl chloride.
  • R–OH + HCl —[anhyd. ZnCl2]→ R–Cl + H2O — 1° and 2° alcohols need anhydrous ZnCl2 catalyst; 3° alcohols react merely by shaking with conc. HCl at room temp. Reactivity of alcohols with HX: 3° > 2° > 1°.
  • R–OH + NaBr + H2SO4 → R–Br + NaHSO4 + H2O (or constant-boiling 48% HBr).
  • 3 R–OH + PX3 → 3 R–X + H3PO3 (X = Cl, Br)  |  R–OH + PCl5 → R–Cl + POCl3 + HCl  |  R–OH + red P/X2 → R–X (PX3 generated in situ for Br2, I2).
  • Why Phenols Don't React: Aryl halides cannot be prepared from phenols using HX/PX3/SOCl2 because the C–O bond in phenol has partial double-bond character and is too strong to break!

2. From Hydrocarbons (6.4.2)

  • Free Radical Halogenation of Alkanes: CH3CH2CH2CH3 + Cl2 (UV / Δ) → 1-Chlorobutane + 2-Chlorobutane. Gives a complex mixture of mono- & polyhalo isomers (poor yield of single product). Example 6.3: (CH3)2CHCH2CH3 gives 4 monochloro isomers; Exercise 6.5: Cyclopentane (C5H10) gives a single monochloro product in sunlight.
  • Addition of HX to Alkenes: Follows Markovnikov's rule (CH3CH=CH2 + HI → CH3CH(I)CH3 major + CH3CH2CH2I minor). With HBr + peroxide, anti-Markovnikov addition occurs (Example 6.4(iii): C6H5CH2CH=CH2 + HBr/peroxide → C6H5CH2CH2CH2Br).
  • Addition of Halogens (Unsaturation Test): Passing alkene into reddish-brown Br2 in CCl4 discharges the colour, yielding colourless vic-dibromides.

3. Halogen Exchange Reactions (6.4.3) — Guaranteed Exam Named Reactions

Finkelstein Reaction (for Alkyl Iodides):
R–X + NaI —[dry acetone]→ R–I + NaX↓  (X = Cl, Br)
Driving force: Precipitated NaCl/NaBr in dry acetone shifts equilibrium forward by Le Chatelier's Principle.

Swarts Reaction (for Alkyl Fluorides):
H3C–Br + AgF → H3C–F + AgBr  (Metallic fluorides: AgF, Hg2F2, CoF2, or SbF3)

4. Preparation of Haloarenes (6.5)

  • Electrophilic Substitution of Arenes: Toluene + X2 —[Fe / anhyd. FeCl3, dark]→ o-Halotoluene + p-Halotoluene (easily separated by large melting point difference). Iodination is reversible and requires an oxidising agent (HNO3 or HIO4) to oxidise HI; fluorination is avoided due to extreme reactivity.
  • Sandmeyer's Reaction (from Primary Aromatic Amines):
    C6H5NH2 + NaNO2 + HX —[273–278 K]→ C6H5N2+X− (Benzene diazonium halide)
    C6H5N2+X− —[Cu2Cl2 or Cu2Br2]→ C6H5Cl (or C6H5Br) + N2↑
    For iodobenzene, simply shake the diazonium salt with aqueous KI (no Cu2X2 needed!).
Intext 6.2 High-Yield Trap: Why is H2SO4 NOT used with KI when converting an alcohol to an alkyl iodide? Because H2SO4 oxidises the HI formed in situ into I2! Use 95% orthophosphoric acid (H3PO4) instead! Also, never mix up Finkelstein (NaI / dry acetone → R–I) and Swarts (AgF / SbF3 → R–F).

Topic 6.6: Physical Properties: Boiling Points, Crystal Lattice Melting Points, Density & Solubility

Picture stacking identical straight wooden planks in a timber yard versus dumping knobby branched tree stumps in a pile—the straight planks touch along their entire length and lock together tightly, while the rounded stumps barely touch at single points! That exact geometry governs haloalkanes: straight-chain 1-bromobutane boils at 375 K, while spherical 2-bromo-2-methylpropane boils almost 30 degrees lower at 346 K! And when aromatic rings pack into a solid crystal, symmetrical para-dichlorobenzene fits together like hexagonal floor tiles, sending its melting point sky-high!

Pure alkyl halides are colourless, though bromides and iodides develop colour when exposed to light. Many volatile halogen compounds possess a sweet smell. CH3Cl, CH3Br, C2H5Cl, and some chlorofluoromethanes are gases at room temperature; higher members are liquids or solids.

1. Boiling Points

  • Vs Parent Hydrocarbons: Haloalkanes have considerably higher boiling points than hydrocarbons of comparable molecular mass due to greater polarity (dipole–dipole attractions) and stronger van der Waals forces.
  • Effect of Halogen (Same R group): R–I > R–Br > R–Cl > R–F (size, electron cloud, and mass of halogen increase down the group → stronger van der Waals forces). Also increases with carbon chain length.
  • Effect of Branching (Isomers): Boiling point decreases with branching because compact spherical shapes reduce surface area and van der Waals contact:
    1-Bromobutane (375 K) > 2-Bromobutane (364 K) > 2-Bromo-2-methylpropane (346 K)

2. Isomeric Dihalobenzenes: Boiling Point vs Melting Point

IsomerBoiling Point (K)Melting Point (K)Key Exam Reason
ortho-Dichlorobenzene453256Asymmetric; packs less efficiently in solid
meta-Dichlorobenzene446249Asymmetric; lowest m.p. among the three
para-Dichlorobenzene448 (nearly same)323 (Highest!)High symmetry fits closely into crystal lattice!

3. Density (Table 6.3) & Solubility

  • Density: Bromo, iodo, and polychloro derivatives are heavier than water (density > 1 g mL-1). Density rises with number of carbon atoms, number of halogen atoms, and halogen atomic mass:
    n-C3H7Cl (0.89) < n-C3H7Br (1.335) < n-C3H7I (1.747 g/mL)  |  CH2Cl2 (1.336) < CHCl3 (1.489) < CCl4 (1.595 g/mL).
  • Solubility (Exercise 6.12(ii)): Haloalkanes are polar, yet very slightly soluble (immiscible) in water! Why? Dissolving requires breaking intermolecular attractions in R–X and strong hydrogen bonds in water, whereas the new dipole–water attractions formed release less energy than needed to break water's H-bonds. However, they dissolve freely in organic solvents where intermolecular forces have comparable strength.
Watch two sneaky board exam twists: (1) Students confuse boiling point with melting point in o-, m-, p-dichlorobenzene! Their boiling points are nearly the same (~446–453 K), while ONLY the melting point of para-dichlorobenzene (323 K) is sharply higher due to crystal lattice symmetry! (2) Even though R–X is polar, it does NOT dissolve in water because it cannot form or compensate for breaking water's strong hydrogen bonds!

Topic 6.7.1 (1)(a–b): Nucleophilic Substitution: Ambident Nucleophiles, Sₙ2 Umbrella Inversion vs Sₙ1 Carbocation

Imagine trying to open a swinging door while carrying a giant umbrella on a windy street. If the front of the room is blocked by a bulky crowd, you wait for the leaving guest to walk out first before stepping in (SN1: 2 steps). But if the doorway around a tiny carbon atom is clear, the incoming hydroxide ion charges straight through the back door (180° opposite the leaving halide) and flips the three hydrogen bonds inside-out like an umbrella caught in a sudden monsoon gust—that is SN2 backside inversion!

Because the sp3 carbon bears a partial positive charge (Cδ+–Xδ−), electron-rich nucleophiles (Nu−) attack carbon and displace the halide leaving group (X−). In all nucleophilic substitutions of a given R group, leaving-group reactivity is: R–I > R–Br > R–Cl >> R–F (Example 6.6).

1. Key Reagents & Ambident Nucleophiles (Table 6.4 & Example 6.5)

Ambident nucleophiles possess two nucleophilic donor atoms and can link through either site:

ReagentNature & Attacking SiteMajor ProductWhy?
KCNIonic → free [−:C≡N ↔ :C=N:−] attacks via CR–CN (Alkyl cyanide / nitrile)C–C bond is stronger & more stable than C–N bond
AgCNCovalent (Ag–C≡N:) → attacks via N lone pairR–NC (Alkyl isocyanide)Carbon is bonded to Ag; only N lone pair is free
KNO2Ionic [O=N–O−] → attacks via negatively charged OR–O–N=O (Alkyl nitrite)Oxide oxygen carries negative charge
AgNO2Covalent (Ag–O–N=O) → attacks via N lone pairR–NO2 (Nitroalkane)O is covalently held by Ag; N donates lone pair

Other vital Table 6.4 substitutions: aq. NaOH/KOH → ROH; NaOR' → ROR' (ether); NH3 → RNH2; R'COOAg → R'COOR (ester); LiAlH4 → RH.

2. SN2 vs SN1 Mechanisms Side-by-Side (Hughes & Ingold, 1937)

PropertySN2 (Bimolecular)SN1 (Unimolecular)
ExampleCH3Cl + OH− → CH3OH + Cl−(CH3)3CBr + OH− → (CH3)3COH + Br−
Steps & Intermediate1 concerted step; NO intermediate (passes through 5-bonded transition state)2 steps; Step I (slow, RDS) forms planar sp2 carbocation; Step II fast attack
Kinetics / Rate Law2nd order: Rate = k [R–X][Nu−]1st order: Rate = k [R–X] (independent of [Nu−])
Preferred SolventPolar aprotic (e.g., acetone, DMSO)Polar protic (H2O, ROH, CH3COOH — solvation of X− pays cleavage energy)
Substrate Rate OrderCH3X > 1° > 2° > 3° (Relative rates: 30 : 1 : 0.02 : 0 — steric hindrance)3° > 2° > 1° > CH3X (governed by carbocation stability)
Stereochemistry100% Inversion of configuration (backside umbrella flip)Racemisation (front & back attack on planar carbocation)
NCERT Example 6.7 & Allylic/Benzylic Resonance Rule:
• Allylic (CH2=CH–CH2+) and benzylic (C6H5CH2+) halides react rapidly via SN1 despite being 1° because their carbocations are resonance-stabilised!
• Four bromobutanes: SN1 rate: 1-bromobutane < 1-bromo-2-methylpropane < 2-bromobutane < 2-bromo-2-methylpropane (reverse order for SN2!).
• Benzylic series (Ex 6.7(ii) & 6.17): C6H5C(CH3)(C6H5)Br > C6H5CH(C6H5)Br > C6H5CH(CH3)Br > C6H5CH2Br in SN1 (two phenyl rings + methyl stabilise carbocation best; exact reverse order in SN2!).
Watch two classic exam pitfalls: (1) Even though benzyl chloride (C6H5CH2Cl) and allyl chloride look like 1° halides, they undergo SN1 rapidly because resonance stabilises their carbocations! (2) Always state the bonding nature when explaining ambident nucleophiles: KCN is ionic (attacks via C → R–CN), while AgCN is covalent (attacks via N → R–NC)!

Topic 6.7.1 (1)(c): Stereochemistry: Optical Activity, Polarimeter, Chirality, Enantiomers & Racemisation

Hold your left hand directly on top of your right hand, both palms facing down—your thumbs stick out on opposite sides! No matter how you slide or spin them on a table, your left and right hands never superimpose. Back in 1848, Louis Pasteur noticed left-handed and right-handed crystals rotated polarised light in opposite directions, and in 1874 Van't Hoff and Le Bel cracked the mystery: whenever a tetrahedral carbon holds four completely different groups, the molecule becomes left- or right-handed—a chiral molecule!

1. Optical Activity & The Polarimeter

  • Passing ordinary light through a Nicol prism produces plane polarised light (PPL) vibrating in a single plane.
  • Compounds whose solutions rotate the plane of PPL (measured in a polarimeter) are optically active:
    • Dextrorotatory (d or +): Rotates PPL to the right (clockwise).
    • Laevorotatory (l or −): Rotates PPL to the left (anticlockwise).

2. Chirality, Asymmetric Carbon & Enantiomers

  • Asymmetric Carbon (Stereocentre): An sp3 tetrahedral carbon attached to four different atoms or groups.
  • Chiral vs Achiral: Objects or molecules that are non-superimposable on their mirror images (e.g., hands, shoes, butan-2-ol, 2-chlorobutane, BrClCHI, 2-bromopropanoic acid, 2,3-dihydroxypropanal) are chiral (optically active). Molecules superimposable on their mirror images (e.g., propan-2-ol, Fig. 6.5 — rotated 180° matches identically!) are achiral (optically inactive).
  • Enantiomers: Stereoisomers related as non-superimposable mirror images. They share identical melting point, boiling point, solubility, and refractive index, differing only in the direction they rotate PPL (+ vs −).
  • Racemic Mixture (dl or ±) & Racemisation: An equimolar (50 : 50) mixture of (+) and (−) enantiomers has zero net optical rotation because one isomer's rotation cancels the other's (e.g., (±)-butan-2-ol). Converting an optically active enantiomer into a racemic mixture is called racemisation.

3. Stereochemical Outcomes in Substitution Reactions

OutcomeWhat Happens at the Stereocentre?Classic NCERT Example
Retention of ConfigurationSpatial arrangement around asymmetric C is preserved (often when no bond to stereocentre breaks)(−)-2-Methylbutan-1-ol + HCl → (+)-1-Chloro-2-methylbutane
Inversion of ConfigurationIncoming Nu− attacks 180° opposite leaving group → 100% flipped configuration (SN2)(−)-2-Bromooctane + OH− → (+)-Octan-2-ol
RacemisationPlanar sp2 carbocation intermediate (achiral!) is attacked equally from both faces → 50:50 (±) mixture (SN1)Optically active 2-Bromobutane hydrolysis → (±)-Butan-2-ol
Super Important NCERT Note: Sign of optical rotation (+ or −) is not rigidly tied to absolute configuration! For example, when (−)-2-methylbutan-1-ol reacts with HCl, no bond to the stereocentre breaks so it proceeds with retention, yet the product (+)-1-chloro-2-methylbutane flips sign from (−) to (+)! Also, a racemic mixture is optically inactive due to external compensation (equal opposite rotations cancelling), NOT because its individual molecules are achiral!

Topic 6.7.1 (2 – 3): β-Elimination (Saytzeff Rule), Substitution vs Elimination, Grignard Reagents & Wurtz Reaction

Drop 2-bromopentane into potassium hydroxide, and the solvent decides everything! In water (aq. KOH), OH− behaves like a polite replacement guest and yields an alcohol. Boil the exact same halide in alcohol (alc. KOH), and OH−/RO− turns into an aggressive proton thief—snatching a β-hydrogen next door, kicking out bromide, and snapping in a C=C double bond! Even more dramatic: drop dry magnesium turnings into alkyl halide in bone-dry ether and you forge a Grignard reagent—so hyper-reactive that a single droplet of moisture destroys it instantly!

1. β-Elimination (Dehydrohalogenation) & Saytzeff / Zaitsev Rule (1875)

When a haloalkane carrying a β-hydrogen (on the carbon adjacent to the α-carbon holding X) is heated with alcoholic KOH (or NaOEt/EtOH), H is eliminated from the β-carbon and X from the α-carbon to form an alkene.

Saytzeff (Zaitsev) Rule: In dehydrohalogenation, the preferred (major) product is the alkene that has the greater number of alkyl groups attached to the doubly bonded carbon atoms (more substituted alkene).

NCERT Example: CH3CH2CH2CH(Br)CH3 (2-Bromopentane) + alc. KOH, Δ →
• Pent-2-ene (81%, Major): CH3–CH2–CH=CH–CH3 (2 alkyl groups on C=C)
• Pent-1-ene (19%, Minor): CH3–CH2–CH2–CH=CH2 (1 alkyl group on C=C)
NCERT Exercise 6.10 Major Alkenes (with NaOEt / EtOH):
• 1-Bromo-1-methylcyclohexane → 1-Methylcyclohexene (trisubstituted C=C, major) vs methylenecyclohexane.
• 2-Chloro-2-methylbutane → 2-Methylbut-2-ene (major) vs 2-methylbut-1-ene.
• 2,2,3-Trimethyl-3-bromopentane → 3,4,4-Trimethylpent-2-ene (major).

2. Elimination vs Substitution Competition (Exercise 6.20)

  • Solvent Effect: Aqueous KOH provides hydrated OH− favouring Substitution (Alcohol); Alcoholic KOH generates stronger alkoxide base (RO−) favouring β-Elimination (Alkene).
  • Steric Bulk & Substrate: A bulky base like (CH3)3CO− prefers abstracting an outer β-proton (Elimination) rather than squeezing to carbon; 1° halides favour SN2, 2° depend on base strength/size, 3° halides favour SN1 or Elimination.

3. Reaction with Metals: Grignard Reagents & Wurtz Reaction

  • Grignard Reagent (Victor Grignard, 1900; Nobel Prize 1912):
    CH3CH2Br + Mg —[dry ether]→ CH3CH2MgBr (Alkyl magnesium halide, Rδ−–Mgδ+–Xδ−).
    Here, the C–Mg bond is covalent yet highly polar (carbon pulls electrons from electropositive Mg), while Mg–X is essentially ionic.
  • Why Anhydrous Conditions / Dry Ether? (Exercise 6.12(iii)): Grignard reagents are so reactive they react violently with any proton source—even traces of water, alcohols, or amines—to give hydrocarbons:
    RMgX + H2O → R–H + Mg(OH)X (and with D2O → R–D, Intext 6.9!).
  • Wurtz Reaction: Alkyl halides react with sodium in dry ether to yield symmetrical alkanes with double the carbon atoms: 2 R–X + 2 Na —[dry ether]→ R–R + 2 NaX.
Two guaranteed Board Exam questions: (1) "Why does aq. KOH give alcohol while alc. KOH gives alkene?" — Answer: In aqueous KOH, OH− acts as a nucleophile causing substitution; in alcoholic KOH, alkoxide ions (RO−) act as a strong base abstracting β-H to give β-elimination! (2) Always write dry ether over the arrow for BOTH Grignard formation and Wurtz reaction!

Topic 6.7.2: Reactions of Haloarenes: Low Sₙ Reactivity, –NO₂ Activation, Electrophilic Substitution & Fittig

Try heating chlorobenzene with aqueous NaOH in a normal beaker—nothing happens! To force hydroxide onto that benzene ring, factories have to crank conditions up to 623 K and 300 atmospheres! Why does aryl chlorine cling so stubbornly while alkyl chlorine slips away easily? Because chlorine donates its lone pair into the benzene ring, locking the C–Cl bond with partial double-bond strength! Yet sneak electron-hungry –NO2 groups onto the ortho and para seats, and suddenly even warm water kicks chlorine right out!

1. Why Are Haloarenes Unreactive Toward Nucleophilic Substitution? (4 NCERT Reasons)

  1. Resonance Effect (Partial Double-Bond Character): Lone pairs on Cl conjugate with the benzene π-ring across four resonance structures, giving the C–Cl bond partial double-bond character—harder to break than a single bond.
  2. Difference in Hybridisation of Carbon: Haloarenes bind X to an sp2 carbon (33.3% s-character, more electronegative → holds electron pair tightly), whereas haloalkanes use sp3 carbon (25% s-character). Hence C–Cl bond length is shorter and stronger in chlorobenzene (169 pm) than in haloalkanes (177 pm)! (This also explains Exercise 6.12(i): chlorobenzene has a lower dipole moment than cyclohexyl chloride!)
  3. Instability of Phenyl Cation: Self-ionisation gives a phenyl cation unstabilised by resonance → SN1 mechanism is completely ruled out.
  4. Electronic Repulsion: An incoming electron-rich nucleophile faces electrostatic repulsion from the electron-rich benzene π-cloud.

2. Replacement by –OH (Dow's Conditions) & Effect of –NO2 Groups

Substrate + aq. NaOH (followed by H+)Conditions NeededProduct
Chlorobenzene623 K, 300 atmPhenol
4-Nitrochlorobenzene (p-NO2)443 K4-Nitrophenol
2,4-Dinitrochlorobenzene (o,p-NO2)368 K2,4-Dinitrophenol
2,4,6-Trinitrochlorobenzene (Picryl chloride)Warm H2O (no NaOH!)2,4,6-Trinitrophenol (Picric acid)

Why ortho/para–NO2 works while meta–NO2 has NO effect: During nucleophilic attack, the negative charge in the resonance-stabilised carbanion intermediate appears only at ortho and para carbons relative to Cl. Thus o/p–NO2 groups pull and delocalise that negative charge, whereas a meta–NO2 sits on a carbon that never bears the negative charge!

3. Electrophilic Aromatic Substitution (Example 6.9)

Chlorine is deactivating yet ortho, para-directing! Why?

  • Reactivity is controlled by the stronger –I (inductive) effect: Cl withdraws net electron density, destabilising the carbocation intermediate and making EAS slower than benzene (needs harsher conditions).
  • Orientation is controlled by the +R (resonance) effect: Resonance pushes electron density and stabilises the carbocation specifically at ortho and para positions (para isomer is ALWAYS major due to minimal steric hindrance).
  • 4 Classic EAS Reactions of Chlorobenzene: Halogenation (Cl2 / anhyd. FeCl3 → 1,4-dichlorobenzene major), Nitration (HNO3 + conc. H2SO4 → 1-chloro-4-nitrobenzene major), Sulphonation (conc. H2SO4, Δ → 4-chlorobenzenesulphonic acid major), Friedel-Crafts Alkylation/Acylation (CH3Cl or CH3COCl + anhyd. AlCl3 → 4-chloro derivative major).

4. Reaction with Metals: Wurtz-Fittig & Fittig Reactions

Wurtz-Fittig: C6H5X + 2 Na + R–X —[dry ether]→ C6H5–R (Alkylarene) + 2 NaX
Fittig Reaction: 2 C6H5X + 2 Na —[dry ether]→ C6H5–C6H5 (Diphenyl / Biphenyl) + 2 NaX
NCERT Example 6.9 Exam Mantra: Memorise this golden sentence: "In electrophilic substitution of haloarenes, reactivity is controlled by the stronger inductive (–I) effect (causing deactivation), while orientation is controlled by the resonance (+R) effect (directing to ortho and para positions)!" Also remember: meta–NO2 does NOT activate nucleophilic substitution in chlorobenzene!

Topic 6.8: Polyhalogen Compounds: Chloroform Storage, Iodoform, CCl₄, Freons & DDT

Step into any chemistry stockroom and inspect the chloroform bottle—it is always made of dark amber glass and filled right up to the brim! Leave pure chloroform half-empty in a clear glass bottle on a sunny windowsill, and oxygen plus sunlight quietly turn it into phosgene (COCl2), a deadly war gas! Meanwhile, ultra-stable Freon-12 escapes old refrigerators into the stratosphere to destroy our UV-blocking ozone shield, and DDT lingers silently inside animal fat!

Hydrocarbons carrying more than one halogen atom are called polyhalogen compounds. While hugely useful in industry, medicine, and agriculture, many resist breakdown by soil bacteria and harm human health or the environment.

Compound & FormulaKey UsesHealth / Environmental Hazards & Crucial Exam Fact
Dichloromethane
(Methylene chloride, CH2Cl2)
Paint remover, aerosol propellant, drug process solvent, metal cleaningHarms CNS (impaired hearing/vision, dizziness, nausea, tingling fingers); burns skin & cornea. Highest dipole moment among CH2Cl2 > CHCl3 > CCl4!
Trichloromethane
(Chloroform, CHCl3)
Solvent for fats, alkaloids, iodine; main use today: manufacture of Freon R-22; former anaesthetic (replaced by safer ether)Depresses CNS; chronic exposure damages liver & kidneys (metabolised to phosgene). Oxidised by air in light to poisonous phosgene (COCl2)!
Triiodomethane
(Iodoform, CHI3)
Earlier used as an antiseptic for woundsAntiseptic action is due to liberation of free iodine (I2), NOT iodoform itself! Replaced due to objectionable smell.
Tetrachloromethane
(Carbon tetrachloride, CCl4)
Feedstock for CFCs/refrigerants, pharmaceutical solvent; formerly cleaning fluid & fire extinguisherCauses liver cancer, nerve damage, irregular heartbeat; rises to atmosphere and depletes ozone layer (↑ UV rays → skin cancer).
Freons
(e.g., Freon-12, CCl2F2)
Aerosol propellants, refrigeration, air-conditioning (stable, unreactive, non-toxic, non-corrosive gases)Freon-12 (CCl2F2) made from CCl4 via Swarts reaction. Diffuses unchanged into stratosphere and initiates radical chain reactions destroying O3.
DDT
(p,p'-Dichlorodiphenyltrichloroethane)
First chlorinated organic insecticide (Paul Müller, 1939; Nobel Prize 1948); controlled malaria mosquitoes & typhus liceInsect resistance, high toxicity to fish; chemically stable & fat-soluble → not metabolised, accumulates in fatty tissues (banned in US in 1973).
Photo-oxidation of Chloroform (Why Dark Filled Bottles!):
2 CHCl3 + O2 —[sunlight]→ 2 COCl2 (Phosgene / Carbonyl chloride) + 2 HCl
Storage Rule: Chloroform is stored in closed, dark-coloured bottles completely filled to the brim so that both light and air are excluded!
Three classic 1–2 mark questions every student must nail: (1) Why is chloroform stored in dark bottles filled to the brim? To block light and air so it cannot oxidise into poisonous phosgene (COCl2)! (2) Why was iodoform used as an antiseptic? Because of the liberation of free iodine (I2), not CHI3 itself! (3) Arrange CH2Cl2, CHCl3, CCl4 in decreasing dipole moment (Exercise 6.4): CH2Cl2 (1.60 D) > CHCl3 (1.08 D) > CCl4 (0 D, symmetrical tetrahedral)!

Solved Previous Year Questions (Kerala DHSE & NCERT)

Q1 (Kerala HSE March (Most Repeated) • 3 Marks): Distinguish between SN1 and SN2 mechanisms of nucleophilic substitution in haloalkanes with respect to: (a) Number of steps & intermediate, (b) Order of reaction, (c) Reactivity order of 1°, 2°, 3° halides, and (d) Stereochemistry.

FeatureSN1 MechanismSN2 Mechanism
Steps / Intermediate2 steps; forms planar sp2 carbocation intermediate1 concerted step; no intermediate (5-bonded TS)
Order / Kinetics1st order: Rate = k[R–X]2nd order: Rate = k[R–X][Nu−]
Reactivity Order3° > 2° > 1° > CH3X (carbocation stability)CH3X > 1° > 2° > 3° (steric hindrance)
StereochemistryRacemisation (50:50 dl mixture)100% Inversion of configuration

Q2 (Kerala HSE March / SAY (Classic 4-Point) • 4 Marks): Haloarenes are much less reactive towards nucleophilic substitution reactions than haloalkanes. Explain any three (or four) reasons. How does the presence of –NO2 groups at ortho and para positions affect this reactivity?

Reasons for low reactivity of haloarenes toward SN reactions:

  1. Resonance effect: Lone pairs on halogen conjugate with the benzene π-ring, giving the C–X bond partial double-bond character (harder to cleave).
  2. Hybridisation difference: Halogen is bonded to an sp2 carbon (more electronegative) in haloarenes vs an sp3 carbon in haloalkanes, making the C–Cl bond shorter (169 pm vs 177 pm) and stronger.
  3. Instability of phenyl cation: Self-ionisation forms an unstable phenyl cation unstabilised by resonance, ruling out SN1.
  4. Electronic repulsion: Electron-rich nucleophile is repelled by the electron-rich benzene ring.

Effect of –NO2 groups: Electron-withdrawing –NO2 at o/p positions stabilises the negative charge of the intermediate carbanion via resonance, sharply increasing reactivity (e.g., chlorobenzene needs 623 K/300 atm, 4-nitrochlorobenzene 443 K, 2,4-dinitrochlorobenzene 368 K, and 2,4,6-trinitrochlorobenzene reacts with warm H2O). A meta–NO2 has no effect.

Q3 (Kerala HSE SAY / Model • 2 Marks): Write balanced equations for: (a) Finkelstein reaction and (b) Swarts reaction.

  • (a) Finkelstein reaction: Preparation of alkyl iodides by heating alkyl chloride/bromide with NaI in dry acetone.
    R–X + NaI —[dry acetone]→ R–I + NaX↓ (X = Cl, Br; precipitated NaCl/NaBr drives equilibrium forward).
  • (b) Swarts reaction: Preparation of alkyl fluorides by heating alkyl chloride/bromide with a metallic fluoride (AgF, Hg2F2, CoF2, or SbF3).
    CH3–Br + AgF → CH3–F + AgBr

Q4 (Kerala HSE March • 2 Marks): What are ambident nucleophiles? Haloalkanes react with KCN to form alkyl cyanides, whereas with AgCN they form isocyanides as the chief product. Why?

Ambident nucleophiles are groups possessing two nucleophilic donor atoms that can link through either centre (e.g., CN−, NO2−).

KCN vs AgCN: KCN is predominantly ionic and furnishes free CN− ions in solution; attack happens mainly via the C atom because the C–C bond is more stable than C–N, giving alkyl cyanide (R–CN). In contrast, AgCN is mainly covalent, so C is tied up with Ag and only the nitrogen lone pair is free to donate, giving alkyl isocyanide (R–NC).

Q5 (Kerala HSE March / NCERT Ex 6.20 • 2 Marks): Treatment of alkyl chlorides with aqueous KOH gives alcohols, whereas with alcoholic KOH alkenes are formed. Explain. Identify the major alkene formed when 2-bromopentane is heated with alcoholic KOH.

In aqueous KOH, hydrated OH− ions act as a nucleophile and undergo nucleophilic substitution to give alcohols. In alcoholic KOH, alkoxide ions (RO−) act as a strong base and abstract a β-hydrogen atom, causing β-elimination to yield an alkene.

For 2-bromopentane + alc. KOH, by Saytzeff's rule, the more substituted alkene Pent-2-ene (81%) is the major product (over pent-1-ene, 19%).

Q6 (Kerala HSE SAY / NCERT Ex 6.12 • 2 Marks): Why should Grignard reagents (RMgX) be prepared under strictly anhydrous (dry ether) conditions? Write the reaction of CH3MgBr with H2O.

Grignard reagents are extremely reactive because the C–Mg bond is highly polar (Rδ−–Mgδ+–Xδ−). They react rapidly with even traces of moisture or any proton source (water, alcohols, amines) to form hydrocarbons:

CH3MgBr + H2O → CH4 + Mg(OH)Br

Therefore, moisture must be strictly excluded using anhydrous dry ether.

Q7 (Kerala HSE March / NCERT Ex 6.9 • 2 Marks): Although chlorine is an electron-withdrawing group, it is ortho, para-directing in electrophilic aromatic substitution of chlorobenzene. Explain.

Chlorine withdraws electrons by the stronger inductive (–I) effect and releases electrons by the resonance (+R) effect. The stronger –I effect causes net electron withdrawal, destabilising the intermediate carbocation and causing net deactivation (reactivity controlled by inductive effect). However, +R resonance increases electron density and stabilises the carbocation specifically at ortho and para positions (orientation controlled by resonance effect).

Q8 (Kerala HSE Model / NCERT 6.8 • 2 Marks): Why is chloroform (CHCl3) stored in closed dark-coloured bottles completely filled to the brim? Write the chemical equation.

Chloroform is slowly oxidised by atmospheric oxygen in the presence of light to form an extremely poisonous gas, phosgene (carbonyl chloride, COCl2):

2 CHCl3 + O2 —[light]→ 2 COCl2 + 2 HCl

Storing it in closed dark-coloured bottles completely filled excludes both light and air, preventing phosgene formation.

Q9 (Kerala HSE March • 2 Marks): Write chemical equations to convert: (a) Aniline to chlorobenzene (Sandmeyer's reaction) and (b) Chlorobenzene to diphenyl (Fittig reaction).

  • (a) Sandmeyer's reaction:
    C6H5NH2 + NaNO2 + HCl —[273–278 K]→ C6H5N2+Cl− —[Cu2Cl2/HCl]→ C6H5Cl + N2↑
  • (b) Fittig reaction:
    2 C6H5Cl + 2 Na —[dry ether]→ C6H5–C6H5 (Diphenyl) + 2 NaCl

Q10 (Kerala HSE SAY • 2 Marks): (a) Why is p-dichlorobenzene higher melting than its ortho and meta isomers? (b) Why are haloalkanes, though polar, immiscible with water?

  • (a) Because of its symmetrical structure, p-dichlorobenzene packs more closely and efficiently in the crystal lattice than ortho and meta isomers (m.p. 323 K vs 256 K and 249 K).
  • (b) Dissolving haloalkanes in water requires breaking strong hydrogen bonds between water molecules, and the new haloalkane–water attractions release less energy than needed to break water's H-bonds.

Q11 (Kerala HSE Improvement • 1 Marks): Why is sulphuric acid (H2SO4) not used during the reaction of alcohols with KI to prepare alkyl iodides?

H2SO4 converts KI to HI and then oxidises the HI formed into elemental iodine (I2), preventing alkyl iodide formation. Instead, 95% orthophosphoric acid (H3PO4) is used.

Q12 (Kerala HSE March • 1 Marks): Define: (a) Enantiomers and (b) Racemic mixture. Give one example of a chiral molecule.

  • (a) Enantiomers: Stereoisomers related to each other as non-superimposable mirror images (identical physical properties except opposite rotation of plane polarised light).
  • (b) Racemic mixture: An equimolar (50:50) mixture of d and l enantiomers showing zero net optical rotation (optically inactive, e.g., (±)-butan-2-ol).
  • Example of chiral molecule: Butan-2-ol or 2-Chlorobutane.